Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A steam engine intakes 50g of steam at 100°C per minute and cools it down to 20°C. If latent heat of vaporization of steam is 540 cal g -1 , then the heat rejected by the steam engine per minute is______x 10 3 cal.
Text Solution
Verified by ExpertsThe correct answer is:
31
(31)
Sol. Heat rejected = mL f + mS 
T
= (50 x 540) + 50 (1) (100 - 20)
= 31000 Cal
= 31 x 10 3 Cal
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